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[V1] Optimize block table transfer from CPU to GPU #11401

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Signed-off-by: Woosuk Kwon <[email protected]>
@mergify mergify bot added the ci/build label Dec 22, 2024
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Signed-off-by: Woosuk Kwon <[email protected]>
Signed-off-by: Woosuk Kwon <[email protected]>
Signed-off-by: Woosuk Kwon <[email protected]>
int* d_matrix_tgt = matrix_tgt.data_ptr<int>();

// One thread block per row.
int blocks = n;
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it seems this can easily oversubscribe GPU SMs.

int length = matrix_diff[row_id * 2 + 1];
int end = start + length;
int thread_idx = threadIdx.x;
for (int i = start + thread_idx; i < end; i += blockDim.x) {
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most threads in the block would be idle, e.g. for decoding, there's only one or even no entry changes in the block table.

self.block_table_diff_np[row_idx, 0] = start
# Move-and-append is not allowed.
assert self.block_table_diff_np[row_idx, 1] == 0
self.block_table_diff_np[row_idx, 1] = num_blocks
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for the non-uva case, we still need to keep track of the max-block-table-length, so that apply_diff only needs to copy max-block-table-length columns.

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@WoosukKwon WoosukKwon Dec 23, 2024

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Good point. The problem is, the memcpy API requires the data to be in contiguous memory space: https://docs.nvidia.com/cuda/cuda-runtime-api/group__CUDART__MEMORY.html#group__CUDART__MEMORY_1g85073372f776b4c4d5f89f7124b7bf79

So when the block table tensor has the shape [batch_size, max_model_len] and if we slice over the second dimension, then we have to call the memcpy API batch_size times instead of once.

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