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ARM: 8781/1: Fix Thumb-2 syscall return for binutils 2.29+
[ Upstream commit afc9f65 ] When building the kernel as Thumb-2 with binutils 2.29 or newer, if the assembler has seen the .type directive (via ENDPROC()) for a symbol, it automatically handles the setting of the lowest bit when the symbol is used with ADR. The badr macro on the other hand handles this lowest bit manually. This leads to a jump to a wrong address in the wrong state in the syscall return path: Internal error: Oops - undefined instruction: 0 [#2] SMP THUMB2 Modules linked in: CPU: 0 PID: 652 Comm: modprobe Tainted: G D 4.18.0-rc3+ #8 PC is at ret_fast_syscall+0x4/0x62 LR is at sys_brk+0x109/0x128 pc : [<80101004>] lr : [<801c8a35>] psr: 60000013 Flags: nZCv IRQs on FIQs on Mode SVC_32 ISA ARM Segment none Control: 50c5387d Table: 9e82006a DAC: 00000051 Process modprobe (pid: 652, stack limit = 0x(ptrval)) 80101000 <ret_fast_syscall>: 80101000: b672 cpsid i 80101002: f8d9 2008 ldr.w r2, [r9, #8] 80101006: f1b2 4ffe cmp.w r2, #2130706432 ; 0x7f000000 80101184 <local_restart>: 80101184: f8d9 a000 ldr.w sl, [r9] 80101188: e92d 0030 stmdb sp!, {r4, r5} 8010118c: f01a 0ff0 tst.w sl, torvalds#240 ; 0xf0 80101190: d117 bne.n 801011c2 <__sys_trace> 80101192: 46ba mov sl, r7 80101194: f5ba 7fc8 cmp.w sl, torvalds#400 ; 0x190 80101198: bf28 it cs 8010119a: f04f 0a00 movcs.w sl, #0 8010119e: f3af 8014 nop.w {20} 801011a2: f2af 1ea2 subw lr, pc, torvalds#418 ; 0x1a2 To fix this, add a new symbol name which doesn't have ENDPROC used on it and use that with badr. We can't remove the badr usage since that would would cause breakage with older binutils. Signed-off-by: Vincent Whitchurch <[email protected]> Signed-off-by: Russell King <[email protected]> Signed-off-by: Sasha Levin <[email protected]>
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