--from-file positional parameter not passed to jq since 2.3.5

[brydoncheyney]

After changes made to passing positional parameters to jq, it looks like --from-file filter is broken and the filter for jq must be defined as the jq_filter of yq. This means you can no longer define filters in a file, which is invaluable for more complex constructs.

Example Setup

Define a filter and some yaml data

[yq] cat filter
.foo
[yq] cat data
foo
  a: 1

2.3.4

Positional arguments are broken

[yq] yq -y --arg a b . data
usage: yq [-h] [--yaml-output] [--width WIDTH] [--version]
          jq_filter [files [files ...]]
yq: error: argument files: can't open 'b': [Errno 2] No such file or directory: 'b'

--from-file without jq_filter works

[yq] yq -y --from-file filter data
a: 1

2.3.5

After changes to positional parameters, the --args example now works

[yq] yq -y --arg a b . data
foo:
  a: 1

...but the --from-file example is broken, returning the --help text with a return code 0.

[yq] yq -y --from-file filter data
usage: yq [options] <jq filter> [YAML file...]
          jq_filter [files [files ...]]

yq: Command-line YAML processor - jq wrapper for YAML documents
...
[yq] echo $?
0

trying to define the call with the self identify filter still fails to work, returning no error message but a return code of 2.

[yq] yq -y --from-file filter . data
[yq] echo $?
2

[brydoncheyney]

Updated the issue after further investigation revealed the initial report was over simplified.

[kislyuk]

Thank you for investigating. Looking into this.

[kislyuk]

This should be fixed in v2.3.7. Please test.