-
Notifications
You must be signed in to change notification settings - Fork 612
/
85.py
69 lines (59 loc) · 1.71 KB
/
85.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
'''
Given a 2D binary matrix filled with 0's and 1's, find the largest rectangle containing only 1's and return its area.
Example:
Input:
[
["1","0","1","0","0"],
["1","0","1","1","1"],
["1","1","1","1","1"],
["1","0","0","1","0"]
]
Output: 6
'''
class Solution(object):
def largestRectangleArea(self, heights):
"""
:type heights: List[int]
:rtype: int
"""
if not heights:
return 0
stack = []
result, index = 0, 0
while index < len(heights):
if not stack or heights[index] >= heights[stack[-1]]:
stack.append(index)
index += 1
else:
curr = stack.pop()
if not stack:
area = heights[curr]*index
else:
area = heights[curr] * (index-stack[-1]-1)
result = max(result, area)
while stack:
curr = stack.pop()
if not stack:
area = heights[curr]*index
else:
area = heights[curr] * (index-stack[-1]-1)
result = max(result, area)
return result
def maximalRectangle(self, matrix):
"""
:type matrix: List[List[str]]
:rtype: int
"""
if not matrix:
return 0
m, n = len(matrix), len(matrix[0])
heights = [0 for index in range(n)]
result = 0
for index_i in range(m):
for index_j in range(n):
if matrix[index_i][index_j] != '0':
heights[index_j] = heights[index_j] + 1
else:
heights[index_j] = 0
result = max(result, self.largestRectangleArea(heights))
return result